Optimal. Leaf size=313 \[ -\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}+\frac{16 a \left (-65 a^2 b^2+32 a^4+33 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{63 b^6 d \sqrt{a+b \sin (c+d x)}}-\frac{16 \left (-57 a^2 b^2+32 a^4+21 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{63 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.539254, antiderivative size = 313, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.304, Rules used = {2693, 2865, 2752, 2663, 2661, 2655, 2653} \[ -\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}+\frac{16 a \left (-65 a^2 b^2+32 a^4+33 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{63 b^6 d \sqrt{a+b \sin (c+d x)}}-\frac{16 \left (-57 a^2 b^2+32 a^4+21 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{63 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2693
Rule 2865
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \frac{\cos ^6(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}-\frac{10 \int \frac{\cos ^4(c+d x) \sin (c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{b}\\ &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{40 \int \frac{\cos ^2(c+d x) \left (-\frac{a b}{2}-\frac{1}{2} \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{21 b^3}\\ &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}-\frac{32 \int \frac{a b \left (2 a^2-3 b^2\right )+\frac{1}{4} \left (32 a^4-57 a^2 b^2+21 b^4\right ) \sin (c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{63 b^5}\\ &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}-\frac{\left (8 \left (32 a^4-57 a^2 b^2+21 b^4\right )\right ) \int \sqrt{a+b \sin (c+d x)} \, dx}{63 b^6}+\frac{\left (8 a \left (32 a^4-65 a^2 b^2+33 b^4\right )\right ) \int \frac{1}{\sqrt{a+b \sin (c+d x)}} \, dx}{63 b^6}\\ &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}-\frac{\left (8 \left (32 a^4-57 a^2 b^2+21 b^4\right ) \sqrt{a+b \sin (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}} \, dx}{63 b^6 \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{\left (8 a \left (32 a^4-65 a^2 b^2+33 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}}} \, dx}{63 b^6 \sqrt{a+b \sin (c+d x)}}\\ &=-\frac{2 \cos ^5(c+d x)}{b d \sqrt{a+b \sin (c+d x)}}+\frac{20 \cos ^3(c+d x) (8 a-7 b \sin (c+d x)) \sqrt{a+b \sin (c+d x)}}{63 b^3 d}-\frac{16 \left (32 a^4-57 a^2 b^2+21 b^4\right ) E\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{a+b \sin (c+d x)}}{63 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{16 a \left (32 a^4-65 a^2 b^2+33 b^4\right ) F\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}{63 b^6 d \sqrt{a+b \sin (c+d x)}}-\frac{8 \cos (c+d x) \sqrt{a+b \sin (c+d x)} \left (a \left (32 a^2-33 b^2\right )-3 b \left (8 a^2-7 b^2\right ) \sin (c+d x)\right )}{63 b^5 d}\\ \end{align*}
Mathematica [A] time = 1.4752, size = 273, normalized size = 0.87 \[ \frac{b \cos (c+d x) \left (\left (84 b^4-64 a^2 b^2\right ) \cos (2 (c+d x))+1760 a^2 b^2-256 a^3 b \sin (c+d x)-1024 a^4+404 a b^3 \sin (c+d x)+20 a b^3 \sin (3 (c+d x))+7 b^4 \cos (4 (c+d x))-595 b^4\right )-64 a \left (-65 a^2 b^2+32 a^4+33 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )+64 \left (-57 a^3 b^2-57 a^2 b^3+32 a^4 b+32 a^5+21 a b^4+21 b^5\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} E\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )}{252 b^6 d \sqrt{a+b \sin (c+d x)}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.601, size = 1195, normalized size = 3.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{6}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{b \sin \left (d x + c\right ) + a} \cos \left (d x + c\right )^{6}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{6}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]